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According to Avogadro's Law, equal amount of gases occupy the same volume at ame conditions.

As 10 g of CO2 is mole

mole of SO2 occupy 20 dm3 as well

As 10 g of SO2 is mole

So it occupy / * 20 = * 20 = dm3

10g methane = 10/16 mol = , 10g of SO2 =10/64 mol = This is one quarter of the moles of methane.

Now at the same pressure and temperature mol CH4 occupy 20dm^3 but mol of SO2 will only occupy 20/4 = 5 dm^3

I've only taken AP chem but it seems as though you would need to know more Like the temp and pressure and molar mass of sulfur dioxide. Depending on the level of chemistry your in you could just use PV=nRT but this may be a bit If this is a question from a book, then try to find out they they give you information about methane gas, usually you will need the info for the Yea, thats all i got.

PV/nT(methane)=PV/nT(SO2)

n(mole) methane: gr/molar mass= 10/16=

n(mole) SO2: 10/64=

put them : (same temperature and pressure so we can ignore T and P)

20

V (SO2) = 5 dm^3

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