We know that
Sin(A+B)=sinA cosB +cosA sinB
Now,putting B=A in the above formula,we get
sin(A+A)=sinA cosA+cosA sinA
or,sin 2A=2 sinA cosA (Proved
Yes, and cos2A = cos^2 A - sin^2 A
sin2A= 2sinA*cosA
= sin 2A
= sin ( A + A )
= sinAcosA + cosAsinA
= 2sinA cosA =
sin (A + A) = sin A + cos A
sin (A + A) = sin A + sin A. cos A
sin 2A = A
sin 2A
=sin (A+A)
=sin A cos A+ cos A sin A
=2sinAcosA
yes
yup
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Verified answer
We know that
Sin(A+B)=sinA cosB +cosA sinB
Now,putting B=A in the above formula,we get
sin(A+A)=sinA cosA+cosA sinA
or,sin 2A=2 sinA cosA (Proved
Yes, and cos2A = cos^2 A - sin^2 A
sin2A= 2sinA*cosA
= sin 2A
= sin ( A + A )
= sinAcosA + cosAsinA
= 2sinA cosA =
sin (A + A) = sin A + cos A
sin (A + A) = sin A + sin A. cos A
sin 2A = A
sin 2A
=sin (A+A)
=sin A cos A+ cos A sin A
=2sinAcosA
yes
yup